Optimal. Leaf size=269 \[ \frac {c (g x)^{1+m} \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \, _2F_1\left (\frac {1+m}{4},-p;\frac {5+m}{4};-\frac {b x^4}{a}\right )}{g (1+m)}+\frac {d (g x)^{2+m} \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \, _2F_1\left (\frac {2+m}{4},-p;\frac {6+m}{4};-\frac {b x^4}{a}\right )}{g^2 (2+m)}+\frac {e (g x)^{3+m} \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \, _2F_1\left (\frac {3+m}{4},-p;\frac {7+m}{4};-\frac {b x^4}{a}\right )}{g^3 (3+m)}+\frac {f (g x)^{4+m} \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \, _2F_1\left (\frac {4+m}{4},-p;\frac {8+m}{4};-\frac {b x^4}{a}\right )}{g^4 (4+m)} \]
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Rubi [A]
time = 0.17, antiderivative size = 269, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 4, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {1847, 1350,
372, 371} \begin {gather*} \frac {c (g x)^{m+1} \left (a+b x^4\right )^p \left (\frac {b x^4}{a}+1\right )^{-p} \, _2F_1\left (\frac {m+1}{4},-p;\frac {m+5}{4};-\frac {b x^4}{a}\right )}{g (m+1)}+\frac {d (g x)^{m+2} \left (a+b x^4\right )^p \left (\frac {b x^4}{a}+1\right )^{-p} \, _2F_1\left (\frac {m+2}{4},-p;\frac {m+6}{4};-\frac {b x^4}{a}\right )}{g^2 (m+2)}+\frac {e (g x)^{m+3} \left (a+b x^4\right )^p \left (\frac {b x^4}{a}+1\right )^{-p} \, _2F_1\left (\frac {m+3}{4},-p;\frac {m+7}{4};-\frac {b x^4}{a}\right )}{g^3 (m+3)}+\frac {f (g x)^{m+4} \left (a+b x^4\right )^p \left (\frac {b x^4}{a}+1\right )^{-p} \, _2F_1\left (\frac {m+4}{4},-p;\frac {m+8}{4};-\frac {b x^4}{a}\right )}{g^4 (m+4)} \end {gather*}
Antiderivative was successfully verified.
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Rule 371
Rule 372
Rule 1350
Rule 1847
Rubi steps
\begin {align*} \int (g x)^m \left (c+d x+e x^2+f x^3\right ) \left (a+b x^4\right )^p \, dx &=\int \left ((g x)^m \left (c+e x^2\right ) \left (a+b x^4\right )^p+\frac {(g x)^{1+m} \left (d+f x^2\right ) \left (a+b x^4\right )^p}{g}\right ) \, dx\\ &=\frac {\int (g x)^{1+m} \left (d+f x^2\right ) \left (a+b x^4\right )^p \, dx}{g}+\int (g x)^m \left (c+e x^2\right ) \left (a+b x^4\right )^p \, dx\\ &=\frac {\int \left (d (g x)^{1+m} \left (a+b x^4\right )^p+\frac {f (g x)^{3+m} \left (a+b x^4\right )^p}{g^2}\right ) \, dx}{g}+\int \left (c (g x)^m \left (a+b x^4\right )^p+\frac {e (g x)^{2+m} \left (a+b x^4\right )^p}{g^2}\right ) \, dx\\ &=c \int (g x)^m \left (a+b x^4\right )^p \, dx+\frac {f \int (g x)^{3+m} \left (a+b x^4\right )^p \, dx}{g^3}+\frac {e \int (g x)^{2+m} \left (a+b x^4\right )^p \, dx}{g^2}+\frac {d \int (g x)^{1+m} \left (a+b x^4\right )^p \, dx}{g}\\ &=\left (c \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p}\right ) \int (g x)^m \left (1+\frac {b x^4}{a}\right )^p \, dx+\frac {\left (f \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p}\right ) \int (g x)^{3+m} \left (1+\frac {b x^4}{a}\right )^p \, dx}{g^3}+\frac {\left (e \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p}\right ) \int (g x)^{2+m} \left (1+\frac {b x^4}{a}\right )^p \, dx}{g^2}+\frac {\left (d \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p}\right ) \int (g x)^{1+m} \left (1+\frac {b x^4}{a}\right )^p \, dx}{g}\\ &=\frac {c (g x)^{1+m} \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \, _2F_1\left (\frac {1+m}{4},-p;\frac {5+m}{4};-\frac {b x^4}{a}\right )}{g (1+m)}+\frac {d (g x)^{2+m} \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \, _2F_1\left (\frac {2+m}{4},-p;\frac {6+m}{4};-\frac {b x^4}{a}\right )}{g^2 (2+m)}+\frac {e (g x)^{3+m} \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \, _2F_1\left (\frac {3+m}{4},-p;\frac {7+m}{4};-\frac {b x^4}{a}\right )}{g^3 (3+m)}+\frac {f (g x)^{4+m} \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \, _2F_1\left (\frac {4+m}{4},-p;\frac {8+m}{4};-\frac {b x^4}{a}\right )}{g^4 (4+m)}\\ \end {align*}
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Mathematica [A]
time = 0.27, size = 174, normalized size = 0.65 \begin {gather*} x (g x)^m \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \left (\frac {f x^3 \, _2F_1\left (1+\frac {m}{4},-p;2+\frac {m}{4};-\frac {b x^4}{a}\right )}{4+m}+\frac {c \, _2F_1\left (\frac {1+m}{4},-p;\frac {5+m}{4};-\frac {b x^4}{a}\right )}{1+m}+x \left (\frac {d \, _2F_1\left (\frac {2+m}{4},-p;\frac {6+m}{4};-\frac {b x^4}{a}\right )}{2+m}+\frac {e x \, _2F_1\left (\frac {3+m}{4},-p;\frac {7+m}{4};-\frac {b x^4}{a}\right )}{3+m}\right )\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.04, size = 0, normalized size = 0.00 \[\int \left (g x \right )^{m} \left (f \,x^{3}+e \,x^{2}+d x +c \right ) \left (b \,x^{4}+a \right )^{p}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.39, size = 32, normalized size = 0.12 \begin {gather*} {\rm integral}\left ({\left (f x^{3} + e x^{2} + d x + c\right )} {\left (b x^{4} + a\right )}^{p} \left (g x\right )^{m}, x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\left (g\,x\right )}^m\,{\left (b\,x^4+a\right )}^p\,\left (f\,x^3+e\,x^2+d\,x+c\right ) \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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